1: All new posts must be directly related to topics from the classroom as this blog is just an extension of the class. 2: All comments posted by non-contributors must be signed with either your first name or initials. Failure to do so will result in your post being denied. 3: If you are a contributor and you abuse your privilege, it will be taken away. 4: All classroom rules and expectations are enforced here. We must respect eveyone's opinion and insights. It is ok to disagree, but do so in a respectful manner. 5: Enjoy! :)
We worked on a worksheet that covered converting square metres into square centimetres. Go to http://www.nelson.com/nelson/school/elementary/mathK8/math6/studentcentre/studtryout.html and look at the Ch. 8 activities.
Great question. The side length would only be the same as the height, IF, that side is already a ninety degree angle. This is shown in question 4b, I believe.
I wasnt there on friday and the homework from thursday night i dont understand question 6. It says that you have to make a acute trinangle,right triagnle and a obtuse triangle and the area has to be 6cm2. I dont understand how you would make a Obtuse Triangle or an Acute Triangle because you would need a right angle but a acute triangle and a obtuse triangle only have those angle measurements.
Don't forget that the height of the triangle is measured 90* from the base. You do not necessarily need a 90* (right) angle in the triangle. An acute triangle has ALL acute angles and an obtuse triangle has ONE obtuse angle. (It's impossible to have all obtuse angles). Hope this helps.
You need to have two dimensions (measurements) in order to calculate area of a triangle. The first is the base and the second is the height. The base is the bottom of the triangle and the height is a 90 degree line from the base to the highest point in the triangle. Once you have those two numbers, you need to multiply them together. You would then have to take that number and divide it by two. Don't forget that a triangle is half of a parallelogram. Go to www.mrrumsby.com and check out the area of a parallelogram and area of a triangle lessons for more help.
There were several review questions that we worked on in class. If you go to the Nelson site, located in the 'Links' section of the website, there are questions there that you could work on as a review. If you have any other questions, come in early tomorrow and I will help you through them.
I will be helping move the risers over to Simcoe in the morning. However, we can go over some of the math during the break. Also, read the reply above. The Nelson site is great for a little extra help.
did you guys do any math when i was gone???????
ReplyDelete???????????
jhkcm
Jessey,
ReplyDeleteWe reviewed the sorting of polygons and quadrilaterals. Take a look here to make sure you understand.
http://www.nelson.com/nelson/school/elementary/mathK8/math6/studentcentre/studtryout.html#ch7
Try any of the Ch. 7 activities.
HTH,
Mr. R.
what did we do in math today ? ( tuesday , febuary 10 )
ReplyDeletehg
Hailey,
ReplyDeleteWe worked on a worksheet that covered converting square metres into square centimetres. Go to http://www.nelson.com/nelson/school/elementary/mathK8/math6/studentcentre/studtryout.html and look at the Ch. 8 activities.
Mr. R.
i went on the web site and it was all of the parrelellograms area and triangles area. did we learn that ?
ReplyDeletehg
Hailey,
ReplyDeleteLook at lesson #1 on Unit Relationships. That's the one.
Mr. R.
what did we di in math today ?
ReplyDeletehg
Hailey,
ReplyDeleteChapter 8:2 ---> Area of a parallelogram.
The key thing to remember is that the A = Base x Height.
Base is the length of the bottom of the shape and the height is measured ninety degrees straight up from the base.
HTH,
Mr. R.
What about if your side length is still the same length as your height,then what is the point of the 90 degree angle thing?
ReplyDeleteGenna,
ReplyDeleteGreat question. The side length would only be the same as the height, IF, that side is already a ninety degree angle. This is shown in question 4b, I believe.
Mr. R.
I wasnt there on friday and the homework from thursday night i dont understand question 6. It says that you have to make a acute trinangle,right triagnle and a obtuse triangle and the area has to be 6cm2. I dont understand how you would make a Obtuse Triangle or an Acute Triangle because you would need a right angle but a acute triangle and a obtuse triangle only have those angle measurements.
ReplyDeleteHolly,
ReplyDeleteDon't forget that the height of the triangle is measured 90* from the base. You do not necessarily need a 90* (right) angle in the triangle. An acute triangle has ALL acute angles and an obtuse triangle has ONE obtuse angle. (It's impossible to have all obtuse angles). Hope this helps.
Mr. R.
O okay i just remembered that a little while ago but i thought i should make sure i was right so i wanted ot see what you said. Thank you,
ReplyDeleteHolly
i dont understand how u do the mesurment of a triangle
ReplyDeleteCody,
ReplyDeleteYou need to have two dimensions (measurements) in order to calculate area of a triangle. The first is the base and the second is the height. The base is the bottom of the triangle and the height is a 90 degree line from the base to the highest point in the triangle. Once you have those two numbers, you need to multiply them together. You would then have to take that number and divide it by two. Don't forget that a triangle is half of a parallelogram. Go to www.mrrumsby.com and check out the area of a parallelogram and area of a triangle lessons for more help.
Mr. R.
I think MR.Rumsby makes math a lot of fun MWP
ReplyDeletewas there a study sheet for the math test tommrow .feb 24 2009
ReplyDeleteB.W.S
Bailee,
ReplyDeleteThere were several review questions that we worked on in class. If you go to the Nelson site, located in the 'Links' section of the website, there are questions there that you could work on as a review. If you have any other questions, come in early tomorrow and I will help you through them.
Mr. R.
Mr.R are you going to be in the school tommrow moring . i need a lllooooot of help with the math .
ReplyDeleteplse reply ASAP
Bailee :)
Bailee,
ReplyDeleteI will be helping move the risers over to Simcoe in the morning. However, we can go over some of the math during the break. Also, read the reply above. The Nelson site is great for a little extra help.
Mr. R.
wow we havent posted on here in a looooooooong time ... i just did hehe :):)
ReplyDelete